3x^(3/2)=7x^(3/4)-2

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Solution for 3x^(3/2)=7x^(3/4)-2 equation:


D( x )

x < 0

x < 0

x in <0:+oo)

3*x^(3/2) = 7*x^(3/4)-2 // - 7*x^(3/4)-2

3*x^(3/2)-(7*x^(3/4))+2 = 0

3*x^(3/2)-7*x^(3/4)+2 = 0

t_1 = x^(3/4)

3*t_1^2-7*t_1^1+2 = 0

3*t_1^2-7*t_1+2 = 0

DELTA = (-7)^2-(2*3*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+7)/(2*3) or t_1 = (7-25^(1/2))/(2*3)

t_1 = 2 or t_1 = 1/3

t_1 = 1/3

x^(3/4)-1/3 = 0

1*x^(3/4) = 1/3 // : 1

x^(3/4) = 1/3

x^(3/4) = 1/3 // ^ 4

x^3 = 1/81 // ^ 1/3

x = (1/81)^(1/3)

t_1 = 2

x^(3/4)-2 = 0

1*x^(3/4) = 2 // : 1

x^(3/4) = 2

x^(3/4) = 2 // ^ 4

x^3 = 16 // ^ 1/3

x = 2*2^(1/3)

x in { (1/81)^(1/3), 2*2^(1/3) }

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